As of 2021, the biggest contract in baseball belongs to Los Angeles Angels outfielder Mike Trout. In March 2019, Trout signed a 12-year contract extension worth a whopping $426.5 million. The contract, which runs through the 2030 season, includes a full no-trade clause and makes Trout the highest-paid player in baseball history.
Trout, who is widely considered one of the best players in the game, has lived up to the hype and then some. Since his debut in 2011, he has won three American League MVP awards and has been named an All-Star eight times. He has also finished in the top two in MVP voting in six of the last eight seasons.
Offensively, Trout is a force to be reckoned with. He has a career batting average of .307, with a .416 on-base percentage and .573 slugging percentage. He has also hit over 40 home runs three times and has stolen over 20 bases four times.
Defensively, Trout is no slouch either. He has won two Gold Gloves for his play in the outfield and has recorded over 20 defensive runs saved four times.
Trout's contract extension is the latest in a trend of teams handing out large contracts to their best players. In the past few years, players like Bryce Harper, Manny Machado, and Nolan Arenado have all signed contracts worth over $300 million. While some may question the wisdom of handing out such large contracts, it's hard to argue with the production that players like Trout have provided.
In conclusion, Mike Trout is the player who has the biggest contract in baseball. His 12-year, $426.5 million deal with the Los Angeles Angels makes him the highest-paid player in baseball history. Trout's offensive and defensive skills, along with his MVP awards, All-star appearances, and other accolades make him a worthy recipient of this contract. He's a player that teams can build around for years to come.